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520734117131989 is a prime number
BaseRepresentation
bin111011001100110101101110…
…0000100101111011011010101
32112021202200202221221102112021
41312121223130010233123111
51021223201432441210424
65043301541221453141
7214453540601603245
oct16631533404573325
92467680687842467
10520734117131989
11140a1610a679752
124a4a19162711b1
131947402a45c807
149283946b4bb25
154030751b264e4
hex1d99adc12f6d5

520734117131989 has 2 divisors, whose sum is σ = 520734117131990. Its totient is φ = 520734117131988.

The previous prime is 520734117131867. The next prime is 520734117131993. The reversal of 520734117131989 is 989131711437025.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 441175031363889 + 79559085768100 = 21004167^2 + 8919590^2 .

It is a cyclic number.

It is not a de Polignac number, because 520734117131989 - 215 = 520734117099221 is a prime.

It is a super-2 number, since 2×5207341171319892 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (520734117131489) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 260367058565994 + 260367058565995.

It is an arithmetic number, because the mean of its divisors is an integer number (260367058565995).

Almost surely, 2520734117131989 is an apocalyptic number.

It is an amenable number.

520734117131989 is a deficient number, since it is larger than the sum of its proper divisors (1).

520734117131989 is an equidigital number, since it uses as much as digits as its factorization.

520734117131989 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11430720, while the sum is 61.

The spelling of 520734117131989 in words is "five hundred twenty trillion, seven hundred thirty-four billion, one hundred seventeen million, one hundred thirty-one thousand, nine hundred eighty-nine".