Base | Representation |
---|---|
bin | 10111101100101100000110… |
… | …10011100010111001100111 |
3 | 20211111221212102212002010212 |
4 | 23312112003103202321213 |
5 | 23312310002013010401 |
6 | 302500222310210035 |
7 | 13656020511653021 |
oct | 1366260323427147 |
9 | 224457772762125 |
10 | 52113041141351 |
11 | 1567202015a543 |
12 | 5a17a3405391b |
13 | 2310314541968 |
14 | cc23db113011 |
15 | 6058a6c03dbb |
hex | 2f65834e2e67 |
52113041141351 has 2 divisors, whose sum is σ = 52113041141352. Its totient is φ = 52113041141350.
The previous prime is 52113041141341. The next prime is 52113041141353. The reversal of 52113041141351 is 15314114031125.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-52113041141351 is a prime.
Together with 52113041141353, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (52113041141353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26056520570675 + 26056520570676.
It is an arithmetic number, because the mean of its divisors is an integer number (26056520570676).
Almost surely, 252113041141351 is an apocalyptic number.
52113041141351 is a deficient number, since it is larger than the sum of its proper divisors (1).
52113041141351 is an equidigital number, since it uses as much as digits as its factorization.
52113041141351 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7200, while the sum is 32.
Adding to 52113041141351 its reverse (15314114031125), we get a palindrome (67427155172476).
The spelling of 52113041141351 in words is "fifty-two trillion, one hundred thirteen billion, forty-one million, one hundred forty-one thousand, three hundred fifty-one".
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