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52113041141351 is a prime number
BaseRepresentation
bin10111101100101100000110…
…10011100010111001100111
320211111221212102212002010212
423312112003103202321213
523312310002013010401
6302500222310210035
713656020511653021
oct1366260323427147
9224457772762125
1052113041141351
111567202015a543
125a17a3405391b
132310314541968
14cc23db113011
156058a6c03dbb
hex2f65834e2e67

52113041141351 has 2 divisors, whose sum is σ = 52113041141352. Its totient is φ = 52113041141350.

The previous prime is 52113041141341. The next prime is 52113041141353. The reversal of 52113041141351 is 15314114031125.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-52113041141351 is a prime.

Together with 52113041141353, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (52113041141353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26056520570675 + 26056520570676.

It is an arithmetic number, because the mean of its divisors is an integer number (26056520570676).

Almost surely, 252113041141351 is an apocalyptic number.

52113041141351 is a deficient number, since it is larger than the sum of its proper divisors (1).

52113041141351 is an equidigital number, since it uses as much as digits as its factorization.

52113041141351 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7200, while the sum is 32.

Adding to 52113041141351 its reverse (15314114031125), we get a palindrome (67427155172476).

The spelling of 52113041141351 in words is "fifty-two trillion, one hundred thirteen billion, forty-one million, one hundred forty-one thousand, three hundred fifty-one".