Base | Representation |
---|---|
bin | 110000100010001100… |
… | …111110001111010001 |
3 | 11222111212121201102122 |
4 | 300202030332033101 |
5 | 1323212014333203 |
6 | 35535055424025 |
7 | 3523263606416 |
oct | 604214761721 |
9 | 158455551378 |
10 | 52113433553 |
11 | 20112746a55 |
12 | a124825015 |
13 | 4bb688221c |
14 | 27452b610d |
15 | 15501b2538 |
hex | c2233e3d1 |
52113433553 has 2 divisors, whose sum is σ = 52113433554. Its totient is φ = 52113433552.
The previous prime is 52113433501. The next prime is 52113433571. The reversal of 52113433553 is 35533431125.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 47215813264 + 4897620289 = 217292^2 + 69983^2 .
It is a cyclic number.
It is not a de Polignac number, because 52113433553 - 210 = 52113432529 is a prime.
It is not a weakly prime, because it can be changed into another prime (52113433583) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26056716776 + 26056716777.
It is an arithmetic number, because the mean of its divisors is an integer number (26056716777).
Almost surely, 252113433553 is an apocalyptic number.
It is an amenable number.
52113433553 is a deficient number, since it is larger than the sum of its proper divisors (1).
52113433553 is an equidigital number, since it uses as much as digits as its factorization.
52113433553 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 81000, while the sum is 35.
Adding to 52113433553 its reverse (35533431125), we get a palindrome (87646864678).
The spelling of 52113433553 in words is "fifty-two billion, one hundred thirteen million, four hundred thirty-three thousand, five hundred fifty-three".
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