Base | Representation |
---|---|
bin | 110000100011011000… |
… | …100000100101100101 |
3 | 11222120020212201222020 |
4 | 300203120200211211 |
5 | 1323232102010140 |
6 | 35541044053353 |
7 | 3523624120623 |
oct | 604330404545 |
9 | 158506781866 |
10 | 52133235045 |
11 | 20122941121 |
12 | a12b394259 |
13 | 4bba9c6198 |
14 | 2747b8c513 |
15 | 1551cc46d0 |
hex | c23620965 |
52133235045 has 32 divisors (see below), whose sum is σ = 90373802112. Its totient is φ = 25560256512.
The previous prime is 52133235023. The next prime is 52133235047. The reversal of 52133235045 is 54053233125.
It is not a de Polignac number, because 52133235045 - 25 = 52133235013 is a prime.
It is a super-3 number, since 3×521332350453 (a number of 33 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 52133234997 and 52133235015.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (52133235047) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2366292 + ... + 2388221.
It is an arithmetic number, because the mean of its divisors is an integer number (2824181316).
Almost surely, 252133235045 is an apocalyptic number.
It is an amenable number.
52133235045 is a deficient number, since it is larger than the sum of its proper divisors (38240567067).
52133235045 is a wasteful number, since it uses less digits than its factorization.
52133235045 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4754581.
The product of its (nonzero) digits is 54000, while the sum is 33.
The spelling of 52133235045 in words is "fifty-two billion, one hundred thirty-three million, two hundred thirty-five thousand, forty-five".
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