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5213341453 = 29711754743
BaseRepresentation
bin1001101101011110…
…10100011100001101
3111110022211012000111
410312233110130031
541134103411303
62221152000021
7243122446135
oct46657243415
914408735014
105213341453
112235882661
121015b30011
13651107638
14376557ac5
15207a48b6d
hex136bd470d

5213341453 has 4 divisors (see below), whose sum is σ = 5215099168. Its totient is φ = 5211583740.

The previous prime is 5213341439. The next prime is 5213341531. The reversal of 5213341453 is 3541433125.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5213341453 - 221 = 5211244301 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5213341853) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 874401 + ... + 880342.

It is an arithmetic number, because the mean of its divisors is an integer number (1303774792).

Almost surely, 25213341453 is an apocalyptic number.

It is an amenable number.

5213341453 is a deficient number, since it is larger than the sum of its proper divisors (1757715).

5213341453 is a wasteful number, since it uses less digits than its factorization.

5213341453 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1757714.

The product of its digits is 21600, while the sum is 31.

The square root of 5213341453 is about 72203.4725826951. The cubic root of 5213341453 is about 1733.9585976917.

Adding to 5213341453 its reverse (3541433125), we get a palindrome (8754774578).

The spelling of 5213341453 in words is "five billion, two hundred thirteen million, three hundred forty-one thousand, four hundred fifty-three".

Divisors: 1 2971 1754743 5213341453