Base | Representation |
---|---|
bin | 110000100101001101… |
… | …001001011010110111 |
3 | 11222122101102011021222 |
4 | 300211031021122313 |
5 | 1323312413422444 |
6 | 35544055300555 |
7 | 3524445035426 |
oct | 604515113267 |
9 | 158571364258 |
10 | 52163810999 |
11 | 20139125303 |
12 | a13967a75b |
13 | 4bc4140371 |
14 | 274bc6b2bd |
15 | 1554813eee |
hex | c253496b7 |
52163810999 has 2 divisors, whose sum is σ = 52163811000. Its totient is φ = 52163810998.
The previous prime is 52163810989. The next prime is 52163811019. The reversal of 52163810999 is 99901836125.
It is a happy number.
52163810999 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-52163810999 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 52163810999.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (52163810989) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26081905499 + 26081905500.
It is an arithmetic number, because the mean of its divisors is an integer number (26081905500).
Almost surely, 252163810999 is an apocalyptic number.
52163810999 is a deficient number, since it is larger than the sum of its proper divisors (1).
52163810999 is an equidigital number, since it uses as much as digits as its factorization.
52163810999 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1049760, while the sum is 53.
The spelling of 52163810999 in words is "fifty-two billion, one hundred sixty-three million, eight hundred ten thousand, nine hundred ninety-nine".
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