522540131 has 2 divisors, whose sum is σ = 522540132. Its totient is φ = 522540130.

The previous prime is 522540127. The next prime is 522540133. The reversal of 522540131 is 131045225.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 522540131 - 2² = 522540127 is a prime.

It is a super-2 number, since 2×522540131² = 546096377010994322, which contains 22 as substring.

Together with 522540133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 522540097 and 522540106.

It is not a weakly prime, because it can be changed into another prime (522540133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 261270065 + 261270066.

It is an arithmetic number, because the mean of its divisors is an integer number (261270066).

Almost surely, 2^522540131 is an apocalyptic number.

522540131 is a deficient number, since it is larger than the sum of its proper divisors (1).

522540131 is an equidigital number, since it uses as much as digits as its factorization.

522540131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1200, while the sum is 23.

The square root of 522540131 is about 22859.1367072337. The cubic root of 522540131 is about 805.4524062220.

Adding to 522540131 its reverse (131045225), we get a palindrome (653585356).

The spelling of 522540131 in words is "five hundred twenty-two million, five hundred forty thousand, one hundred thirty-one".