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5232431424047 is a prime number
BaseRepresentation
bin100110000100100010100…
…1101110110001000101111
3200112012211010211212001012
41030021011031312020233
51141212004421032142
615043425032335435
71050013346160632
oct114110515661057
920465733755035
105232431424047
111738075147653
127060b684457b
132bc554417389
14141372b91c19
1591192ea1882
hex4c24537622f

5232431424047 has 2 divisors, whose sum is σ = 5232431424048. Its totient is φ = 5232431424046.

The previous prime is 5232431423987. The next prime is 5232431424049. The reversal of 5232431424047 is 7404241342325.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5232431424047 is a prime.

Together with 5232431424049, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 5232431423995 and 5232431424013.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5232431424049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2616215712023 + 2616215712024.

It is an arithmetic number, because the mean of its divisors is an integer number (2616215712024).

Almost surely, 25232431424047 is an apocalyptic number.

5232431424047 is a deficient number, since it is larger than the sum of its proper divisors (1).

5232431424047 is an equidigital number, since it uses as much as digits as its factorization.

5232431424047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 645120, while the sum is 41.

The spelling of 5232431424047 in words is "five trillion, two hundred thirty-two billion, four hundred thirty-one million, four hundred twenty-four thousand, forty-seven".