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52341154000129 is a prime number
BaseRepresentation
bin10111110011010100111111…
…11001000010110100000001
320212022202200000102221221001
423321222133321002310001
523330024140411001004
6303153105540332001
714011344406163311
oct1371523771026401
9225282600387831
1052341154000129
111574a8389a1625
125a540966a4001
132328998c751c7
14ccd47ab61441
1560b7a82841a4
hex2f9a9fe42d01

52341154000129 has 2 divisors, whose sum is σ = 52341154000130. Its totient is φ = 52341154000128.

The previous prime is 52341154000127. The next prime is 52341154000151. The reversal of 52341154000129 is 92100045114325.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 49782267479025 + 2558886521104 = 7055655^2 + 1599652^2 .

It is a cyclic number.

It is not a de Polignac number, because 52341154000129 - 21 = 52341154000127 is a prime.

Together with 52341154000127, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (52341154000127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26170577000064 + 26170577000065.

It is an arithmetic number, because the mean of its divisors is an integer number (26170577000065).

Almost surely, 252341154000129 is an apocalyptic number.

It is an amenable number.

52341154000129 is a deficient number, since it is larger than the sum of its proper divisors (1).

52341154000129 is an equidigital number, since it uses as much as digits as its factorization.

52341154000129 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 43200, while the sum is 37.

The spelling of 52341154000129 in words is "fifty-two trillion, three hundred forty-one billion, one hundred fifty-four million, one hundred twenty-nine", and thus it is an aban number.