Base | Representation |
---|---|
bin | 10111110011010100111111… |
… | …11001000010110100000001 |
3 | 20212022202200000102221221001 |
4 | 23321222133321002310001 |
5 | 23330024140411001004 |
6 | 303153105540332001 |
7 | 14011344406163311 |
oct | 1371523771026401 |
9 | 225282600387831 |
10 | 52341154000129 |
11 | 1574a8389a1625 |
12 | 5a540966a4001 |
13 | 2328998c751c7 |
14 | ccd47ab61441 |
15 | 60b7a82841a4 |
hex | 2f9a9fe42d01 |
52341154000129 has 2 divisors, whose sum is σ = 52341154000130. Its totient is φ = 52341154000128.
The previous prime is 52341154000127. The next prime is 52341154000151. The reversal of 52341154000129 is 92100045114325.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 49782267479025 + 2558886521104 = 7055655^2 + 1599652^2 .
It is a cyclic number.
It is not a de Polignac number, because 52341154000129 - 21 = 52341154000127 is a prime.
Together with 52341154000127, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (52341154000127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26170577000064 + 26170577000065.
It is an arithmetic number, because the mean of its divisors is an integer number (26170577000065).
Almost surely, 252341154000129 is an apocalyptic number.
It is an amenable number.
52341154000129 is a deficient number, since it is larger than the sum of its proper divisors (1).
52341154000129 is an equidigital number, since it uses as much as digits as its factorization.
52341154000129 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43200, while the sum is 37.
The spelling of 52341154000129 in words is "fifty-two trillion, three hundred forty-one billion, one hundred fifty-four million, one hundred twenty-nine", and thus it is an aban number.
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