Base | Representation |
---|---|
bin | 10111110011010100111111… |
… | …11001000010110100010111 |
3 | 20212022202200000102221221212 |
4 | 23321222133321002310113 |
5 | 23330024140411001101 |
6 | 303153105540332035 |
7 | 14011344406163342 |
oct | 1371523771026427 |
9 | 225282600387855 |
10 | 52341154000151 |
11 | 1574a8389a1645 |
12 | 5a540966a401b |
13 | 2328998c75213 |
14 | ccd47ab61459 |
15 | 60b7a82841bb |
hex | 2f9a9fe42d17 |
52341154000151 has 2 divisors, whose sum is σ = 52341154000152. Its totient is φ = 52341154000150.
The previous prime is 52341154000129. The next prime is 52341154000153. The reversal of 52341154000151 is 15100045114325.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 52341154000151 - 26 = 52341154000087 is a prime.
Together with 52341154000153, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (52341154000153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26170577000075 + 26170577000076.
It is an arithmetic number, because the mean of its divisors is an integer number (26170577000076).
Almost surely, 252341154000151 is an apocalyptic number.
52341154000151 is a deficient number, since it is larger than the sum of its proper divisors (1).
52341154000151 is an equidigital number, since it uses as much as digits as its factorization.
52341154000151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12000, while the sum is 32.
Adding to 52341154000151 its reverse (15100045114325), we get a palindrome (67441199114476).
The spelling of 52341154000151 in words is "fifty-two trillion, three hundred forty-one billion, one hundred fifty-four million, one hundred fifty-one", and thus it is an aban number.
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