Base | Representation |
---|---|
bin | 100110001001100011100… |
… | …0101111110111010001100 |
3 | 200120020121122110020101112 |
4 | 1030103013011332322030 |
5 | 1141401033241214000 |
6 | 15052405403431152 |
7 | 1050544251335141 |
oct | 114230705767214 |
9 | 20506548406345 |
10 | 5243200335500 |
11 | 17416a0999176 |
12 | 7082012254b8 |
13 | 2c057c4c112a |
14 | 141ab50aa3c8 |
15 | 915c35e5235 |
hex | 4c4c717ee8c |
5243200335500 has 48 divisors (see below), whose sum is σ = 11596100880000. Its totient is φ = 2070732268800.
The previous prime is 5243200335493. The next prime is 5243200335511. The reversal of 5243200335500 is 55330023425.
It is a super-2 number, since 2×52432003355002 (a number of 26 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 66330125 + ... + 66409124.
It is an arithmetic number, because the mean of its divisors is an integer number (241585435000).
Almost surely, 25243200335500 is an apocalyptic number.
5243200335500 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
5243200335500 is an abundant number, since it is smaller than the sum of its proper divisors (6352900544500).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
5243200335500 is a wasteful number, since it uses less digits than its factorization.
5243200335500 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 132739347 (or 132739335 counting only the distinct ones).
The product of its (nonzero) digits is 54000, while the sum is 32.
Adding to 5243200335500 its reverse (55330023425), we get a palindrome (5298530358925).
The spelling of 5243200335500 in words is "five trillion, two hundred forty-three billion, two hundred million, three hundred thirty-five thousand, five hundred".
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