Base | Representation |
---|---|
bin | 110000111001010001… |
… | …000001000001111111 |
3 | 12000111211201002210221 |
4 | 300321101001001333 |
5 | 1330010043311120 |
6 | 40041321042211 |
7 | 3536002530565 |
oct | 607121010177 |
9 | 160454632727 |
10 | 52500369535 |
11 | 202a10a9759 |
12 | a212326367 |
13 | 4c48a9b423 |
14 | 2780839a35 |
15 | 15741450aa |
hex | c3944107f |
52500369535 has 16 divisors (see below), whose sum is σ = 63980712576. Its totient is φ = 41347567008.
The previous prime is 52500369529. The next prime is 52500369587. The reversal of 52500369535 is 53596300525.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 52500369535 - 231 = 50352885887 is a prime.
It is a super-2 number, since 2×525003695352 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 52500369491 and 52500369500.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 496884 + ... + 593206.
It is an arithmetic number, because the mean of its divisors is an integer number (3998794536).
Almost surely, 252500369535 is an apocalyptic number.
52500369535 is a deficient number, since it is larger than the sum of its proper divisors (11480343041).
52500369535 is a wasteful number, since it uses less digits than its factorization.
52500369535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 98022.
The product of its (nonzero) digits is 607500, while the sum is 43.
The spelling of 52500369535 in words is "fifty-two billion, five hundred million, three hundred sixty-nine thousand, five hundred thirty-five".
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