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5251262837 is a prime number
BaseRepresentation
bin1001110001111111…
…11110100101110101
3111112222011210101012
410320333332211311
541223310402322
62225024442005
7244062666122
oct47077764565
914488153335
105251262837
112255223547
121026779305
13658c24022
1437b5c9749
1520b039ae2
hex138ffe975

5251262837 has 2 divisors, whose sum is σ = 5251262838. Its totient is φ = 5251262836.

The previous prime is 5251262833. The next prime is 5251262839. The reversal of 5251262837 is 7382621525.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4754240401 + 497022436 = 68951^2 + 22294^2 .

It is a cyclic number.

It is not a de Polignac number, because 5251262837 - 22 = 5251262833 is a prime.

It is a super-2 number, since 2×52512628372 = 55151522766514577138, which contains 22 as substring.

Together with 5251262839, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 5251262794 and 5251262803.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5251262831) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2625631418 + 2625631419.

It is an arithmetic number, because the mean of its divisors is an integer number (2625631419).

Almost surely, 25251262837 is an apocalyptic number.

It is an amenable number.

5251262837 is a deficient number, since it is larger than the sum of its proper divisors (1).

5251262837 is an equidigital number, since it uses as much as digits as its factorization.

5251262837 is an evil number, because the sum of its binary digits is even.

The product of its digits is 201600, while the sum is 41.

The square root of 5251262837 is about 72465.5976101764. The cubic root of 5251262837 is about 1738.1526654002.

The spelling of 5251262837 in words is "five billion, two hundred fifty-one million, two hundred sixty-two thousand, eight hundred thirty-seven".