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52513102333135 = 581111294861357
BaseRepresentation
bin10111111000010101010001…
…10011111000010011001111
320212221012111101120022111001
423330022220303320103033
523340333313144130020
6303404104114041131
714026642425663523
oct1374125063702317
9225835441508431
1052513102333135
1115806755287164
125a814838791a7
13233bc6c756552
14cd790d483d83
15610ebdb8850a
hex2fc2a8cf84cf

52513102333135 has 8 divisors (see below), whose sum is σ = 63023492016576. Its totient is φ = 42005302388640.

The previous prime is 52513102333099. The next prime is 52513102333151. The reversal of 52513102333135 is 53133320131525.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 52513102333135 - 239 = 51963346519247 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 52513102333094 and 52513102333103.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 647390124 + ... + 647471233.

It is an arithmetic number, because the mean of its divisors is an integer number (7877936502072).

Almost surely, 252513102333135 is an apocalyptic number.

52513102333135 is a deficient number, since it is larger than the sum of its proper divisors (10510389683441).

52513102333135 is a wasteful number, since it uses less digits than its factorization.

52513102333135 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1294869473.

The product of its (nonzero) digits is 121500, while the sum is 37.

The spelling of 52513102333135 in words is "fifty-two trillion, five hundred thirteen billion, one hundred two million, three hundred thirty-three thousand, one hundred thirty-five".

Divisors: 1 5 8111 40555 1294861357 6474306785 10502620466627 52513102333135