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5253002555503 = 13259396183917
BaseRepresentation
bin100110001110000111101…
…0110011111000001101111
3200121011220210001121100211
41030130033112133001233
51142031122123234003
615101110203203251
71051342205000053
oct114341726370157
920534823047324
105253002555503
111745870aa713a
1270a097b16527
132c1482220901
14142364c67c63
1591998e3696d
hex4c70f59f06f

5253002555503 has 4 divisors (see below), whose sum is σ = 5253398752680. Its totient is φ = 5252606358328.

The previous prime is 5253002555473. The next prime is 5253002555579. The reversal of 5253002555503 is 3055552003525.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5253002555503 - 229 = 5252465684591 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5253002555303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 198078700 + ... + 198105217.

It is an arithmetic number, because the mean of its divisors is an integer number (1313349688170).

Almost surely, 25253002555503 is an apocalyptic number.

5253002555503 is a deficient number, since it is larger than the sum of its proper divisors (396197177).

5253002555503 is a wasteful number, since it uses less digits than its factorization.

5253002555503 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 396197176.

The product of its (nonzero) digits is 562500, while the sum is 40.

It can be divided in two parts, 525300 and 2555503, that added together give a palindrome (3080803).

The spelling of 5253002555503 in words is "five trillion, two hundred fifty-three billion, two million, five hundred fifty-five thousand, five hundred three".

Divisors: 1 13259 396183917 5253002555503