Base | Representation |
---|---|
bin | 10111111001001001101000… |
… | …11011011111010000010111 |
3 | 20220000220001120200001111111 |
4 | 23330210310123133100113 |
5 | 23341313401411144421 |
6 | 303425033432315451 |
7 | 14031656163626524 |
oct | 1374446433372027 |
9 | 226026046601444 |
10 | 52541214553111 |
11 | 15817670961109 |
12 | 5a86a0a542b87 |
13 | 23417cc9a5c3b |
14 | cd9018cc614b |
15 | 611ab6bb9ee1 |
hex | 2fc9346df417 |
52541214553111 has 4 divisors (see below), whose sum is σ = 52541238530224. Its totient is φ = 52541190576000.
The previous prime is 52541214553073. The next prime is 52541214553151. The reversal of 52541214553111 is 11135541214525.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-52541214553111 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (52541214553151) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8329290 + ... + 13208311.
It is an arithmetic number, because the mean of its divisors is an integer number (13135309632556).
Almost surely, 252541214553111 is an apocalyptic number.
52541214553111 is a deficient number, since it is larger than the sum of its proper divisors (23977113).
52541214553111 is a wasteful number, since it uses less digits than its factorization.
52541214553111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23977112.
The product of its digits is 120000, while the sum is 40.
Adding to 52541214553111 its reverse (11135541214525), we get a palindrome (63676755767636).
The spelling of 52541214553111 in words is "fifty-two trillion, five hundred forty-one billion, two hundred fourteen million, five hundred fifty-three thousand, one hundred eleven".
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