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52541214553111 = 243951121537601
BaseRepresentation
bin10111111001001001101000…
…11011011111010000010111
320220000220001120200001111111
423330210310123133100113
523341313401411144421
6303425033432315451
714031656163626524
oct1374446433372027
9226026046601444
1052541214553111
1115817670961109
125a86a0a542b87
1323417cc9a5c3b
14cd9018cc614b
15611ab6bb9ee1
hex2fc9346df417

52541214553111 has 4 divisors (see below), whose sum is σ = 52541238530224. Its totient is φ = 52541190576000.

The previous prime is 52541214553073. The next prime is 52541214553151. The reversal of 52541214553111 is 11135541214525.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-52541214553111 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (52541214553151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8329290 + ... + 13208311.

It is an arithmetic number, because the mean of its divisors is an integer number (13135309632556).

Almost surely, 252541214553111 is an apocalyptic number.

52541214553111 is a deficient number, since it is larger than the sum of its proper divisors (23977113).

52541214553111 is a wasteful number, since it uses less digits than its factorization.

52541214553111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 23977112.

The product of its digits is 120000, while the sum is 40.

Adding to 52541214553111 its reverse (11135541214525), we get a palindrome (63676755767636).

The spelling of 52541214553111 in words is "fifty-two trillion, five hundred forty-one billion, two hundred fourteen million, five hundred fifty-three thousand, one hundred eleven".

Divisors: 1 2439511 21537601 52541214553111