Base | Representation |
---|---|
bin | 10111111001001001101000… |
… | …11011011111010000111111 |
3 | 20220000220001120200001112222 |
4 | 23330210310123133100333 |
5 | 23341313401411200101 |
6 | 303425033432315555 |
7 | 14031656163626612 |
oct | 1374446433372077 |
9 | 226026046601488 |
10 | 52541214553151 |
11 | 15817670961145 |
12 | 5a86a0a542bbb |
13 | 23417cc9a5c6c |
14 | cd9018cc6179 |
15 | 611ab6bba01b |
hex | 2fc9346df43f |
52541214553151 has 2 divisors, whose sum is σ = 52541214553152. Its totient is φ = 52541214553150.
The previous prime is 52541214553073. The next prime is 52541214553153. The reversal of 52541214553151 is 15135541214525.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-52541214553151 is a prime.
Together with 52541214553153, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (52541214553153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26270607276575 + 26270607276576.
It is an arithmetic number, because the mean of its divisors is an integer number (26270607276576).
Almost surely, 252541214553151 is an apocalyptic number.
52541214553151 is a deficient number, since it is larger than the sum of its proper divisors (1).
52541214553151 is an equidigital number, since it uses as much as digits as its factorization.
52541214553151 is an evil number, because the sum of its binary digits is even.
The product of its digits is 600000, while the sum is 44.
Adding to 52541214553151 its reverse (15135541214525), we get a palindrome (67676755767676).
The spelling of 52541214553151 in words is "fifty-two trillion, five hundred forty-one billion, two hundred fourteen million, five hundred fifty-three thousand, one hundred fifty-one".
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