Base | Representation |
---|---|
bin | 10111111001001001101000… |
… | …11011011111010000011001 |
3 | 20220000220001120200001111120 |
4 | 23330210310123133100121 |
5 | 23341313401411144423 |
6 | 303425033432315453 |
7 | 14031656163626526 |
oct | 1374446433372031 |
9 | 226026046601446 |
10 | 52541214553113 |
11 | 15817670961110 |
12 | 5a86a0a542b89 |
13 | 23417cc9a5c40 |
14 | cd9018cc614d |
15 | 611ab6bb9ee3 |
hex | 2fc9346df419 |
52541214553113 has 32 divisors (see below), whose sum is σ = 82303059750912. Its totient is φ = 29393423016000.
The previous prime is 52541214553073. The next prime is 52541214553151. The reversal of 52541214553113 is 31135541214525.
It is not a de Polignac number, because 52541214553113 - 210 = 52541214552089 is a prime.
It is not an unprimeable number, because it can be changed into a prime (52541214553153) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 53588338 + ... + 54559988.
It is an arithmetic number, because the mean of its divisors is an integer number (2571970617216).
Almost surely, 252541214553113 is an apocalyptic number.
It is an amenable number.
52541214553113 is a deficient number, since it is larger than the sum of its proper divisors (29761845197799).
52541214553113 is a wasteful number, since it uses less digits than its factorization.
52541214553113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1097725.
The product of its digits is 360000, while the sum is 42.
Adding to 52541214553113 its reverse (31135541214525), we get a palindrome (83676755767638).
The spelling of 52541214553113 in words is "fifty-two trillion, five hundred forty-one billion, two hundred fourteen million, five hundred fifty-three thousand, one hundred thirteen".
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