Base | Representation |
---|---|
bin | 10111111001001101111101… |
… | …00101011000111010111011 |
3 | 20220001010001010010002201221 |
4 | 23330212332211120322323 |
5 | 23341333123243420121 |
6 | 303430055432052511 |
7 | 14032100500220506 |
oct | 1374467645307273 |
9 | 226033033102657 |
10 | 52543532404411 |
11 | 158186502650a4 |
12 | 5a87356834137 |
13 | 2341aabc5b499 |
14 | cd9198a8013d |
15 | 611ba0415b41 |
hex | 2fc9be958ebb |
52543532404411 has 2 divisors, whose sum is σ = 52543532404412. Its totient is φ = 52543532404410.
The previous prime is 52543532404409. The next prime is 52543532404457. The reversal of 52543532404411 is 11440423534525.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 52543532404411 - 21 = 52543532404409 is a prime.
Together with 52543532404409, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (52543532414411) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26271766202205 + 26271766202206.
It is an arithmetic number, because the mean of its divisors is an integer number (26271766202206).
Almost surely, 252543532404411 is an apocalyptic number.
52543532404411 is a deficient number, since it is larger than the sum of its proper divisors (1).
52543532404411 is an equidigital number, since it uses as much as digits as its factorization.
52543532404411 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152000, while the sum is 43.
Adding to 52543532404411 its reverse (11440423534525), we get a palindrome (63983955938936).
The spelling of 52543532404411 in words is "fifty-two trillion, five hundred forty-three billion, five hundred thirty-two million, four hundred four thousand, four hundred eleven".
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