Base | Representation |
---|---|
bin | 110000111011111000… |
… | …110000110100100111 |
3 | 12000121220110012112012 |
4 | 300323320300310213 |
5 | 1330102322441320 |
6 | 40045531344435 |
7 | 3540045356231 |
oct | 607370606447 |
9 | 160556405465 |
10 | 52544343335 |
11 | 20313a03940 |
12 | a224bb211b |
13 | 4c54c26923 |
14 | 2786605251 |
15 | 1577e2e4c5 |
hex | c3be30d27 |
52544343335 has 32 divisors (see below), whose sum is σ = 69197939712. Its totient is φ = 37985207680.
The previous prime is 52544343301. The next prime is 52544343337. The reversal of 52544343335 is 53334344525.
It is not a de Polignac number, because 52544343335 - 220 = 52543294759 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 52544343292 and 52544343301.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (52544343337) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 20661074 + ... + 20663616.
It is an arithmetic number, because the mean of its divisors is an integer number (2162435616).
Almost surely, 252544343335 is an apocalyptic number.
52544343335 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
52544343335 is a deficient number, since it is larger than the sum of its proper divisors (16653596377).
52544343335 is a wasteful number, since it uses less digits than its factorization.
52544343335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4663.
The product of its digits is 1296000, while the sum is 41.
The spelling of 52544343335 in words is "fifty-two billion, five hundred forty-four million, three hundred forty-three thousand, three hundred thirty-five".
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