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52553335020341 is a prime number
BaseRepresentation
bin10111111001100000001101…
…10111011001101100110101
320220002001100021110120211012
423330300012313121230311
523342013212231122331
6303434400244122005
714032565430121631
oct1374600667315465
9226061307416735
1052553335020341
1115821820613581
125a89231696305
1323429b1a9923c
14cd9848901dc1
15612075cd482b
hex2fcc06dd9b35

52553335020341 has 2 divisors, whose sum is σ = 52553335020342. Its totient is φ = 52553335020340.

The previous prime is 52553335020323. The next prime is 52553335020343. The reversal of 52553335020341 is 14302053335525.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 50694827200900 + 1858507819441 = 7120030^2 + 1363271^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-52553335020341 is a prime.

Together with 52553335020343, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (52553335020343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26276667510170 + 26276667510171.

It is an arithmetic number, because the mean of its divisors is an integer number (26276667510171).

Almost surely, 252553335020341 is an apocalyptic number.

It is an amenable number.

52553335020341 is a deficient number, since it is larger than the sum of its proper divisors (1).

52553335020341 is an equidigital number, since it uses as much as digits as its factorization.

52553335020341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 810000, while the sum is 41.

Adding to 52553335020341 its reverse (14302053335525), we get a palindrome (66855388355866).

The spelling of 52553335020341 in words is "fifty-two trillion, five hundred fifty-three billion, three hundred thirty-five million, twenty thousand, three hundred forty-one".