Base | Representation |
---|---|
bin | 111011101111111001101100… |
… | …1111001110011000101001111 |
3 | 2112220211101020120020002120210 |
4 | 1313133303121321303011033 |
5 | 1022341130103201440210 |
6 | 5101431421502413503 |
7 | 215461645054350114 |
oct | 16737633171630517 |
9 | 2486741216202523 |
10 | 525553034015055 |
11 | 142503876620272 |
12 | 4ab3b847891293 |
13 | 19733591390337 |
14 | 93acc8c91290b |
15 | 40b5c919e0e20 |
hex | 1ddfcd9e7314f |
525553034015055 has 64 divisors (see below), whose sum is σ = 874780738191360. Its totient is φ = 269139724790400.
The previous prime is 525553034015047. The next prime is 525553034015083. The reversal of 525553034015055 is 550510430355525.
It is not a de Polignac number, because 525553034015055 - 23 = 525553034015047 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 525553034014995 and 525553034015013.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 105043300 + ... + 109932710.
It is an arithmetic number, because the mean of its divisors is an integer number (13668449034240).
Almost surely, 2525553034015055 is an apocalyptic number.
525553034015055 is a deficient number, since it is larger than the sum of its proper divisors (349227704176305).
525553034015055 is a wasteful number, since it uses less digits than its factorization.
525553034015055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4891252.
The product of its (nonzero) digits is 5625000, while the sum is 48.
The spelling of 525553034015055 in words is "five hundred twenty-five trillion, five hundred fifty-three billion, thirty-four million, fifteen thousand, fifty-five".
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