Base | Representation |
---|---|
bin | 10111111011001111111010… |
… | …11100011100100001010111 |
3 | 20220021210010210101110200012 |
4 | 23331213331130130201113 |
5 | 23344004022431014312 |
6 | 303522115213110435 |
7 | 14040120532236314 |
oct | 1375477534344127 |
9 | 226253123343605 |
10 | 52613306501207 |
11 | 158451a5991801 |
12 | 5a98989a8841b |
13 | 234854b64c4aa |
14 | cdc6d768dd0b |
15 | 6138d5ca2322 |
hex | 2fd9fd71c857 |
52613306501207 has 8 divisors (see below), whose sum is σ = 52695502164480. Its totient is φ = 52531111991160.
The previous prime is 52613306501111. The next prime is 52613306501299. The reversal of 52613306501207 is 70210560331625.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-52613306501207 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (52613306501807) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 163585082 + ... + 163906392.
It is an arithmetic number, because the mean of its divisors is an integer number (6586937770560).
Almost surely, 252613306501207 is an apocalyptic number.
52613306501207 is a deficient number, since it is larger than the sum of its proper divisors (82195663273).
52613306501207 is a wasteful number, since it uses less digits than its factorization.
52613306501207 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 576613.
The product of its (nonzero) digits is 226800, while the sum is 41.
The spelling of 52613306501207 in words is "fifty-two trillion, six hundred thirteen billion, three hundred six million, five hundred one thousand, two hundred seven".
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