Base | Representation |
---|---|
bin | 110001000010100000… |
… | …110011101111010111 |
3 | 12000220122121202202120 |
4 | 301002200303233113 |
5 | 1330314302114333 |
6 | 40104542111023 |
7 | 3542565254631 |
oct | 610240635727 |
9 | 160818552676 |
10 | 52655504343 |
11 | 20370728842 |
12 | a25627b473 |
13 | 4c71c77580 |
14 | 279729da51 |
15 | 1582a8adb3 |
hex | c42833bd7 |
52655504343 has 32 divisors (see below), whose sum is σ = 77714347200. Its totient is φ = 31502048256.
The previous prime is 52655504311. The next prime is 52655504371. The reversal of 52655504343 is 34340555625.
It is a happy number.
52655504343 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 52655504343 - 25 = 52655504311 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 52655504295 and 52655504304.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (52655504303) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1845873 + ... + 1874181.
It is an arithmetic number, because the mean of its divisors is an integer number (2428573350).
Almost surely, 252655504343 is an apocalyptic number.
52655504343 is a deficient number, since it is larger than the sum of its proper divisors (25058842857).
52655504343 is a wasteful number, since it uses less digits than its factorization.
52655504343 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 29651.
The product of its (nonzero) digits is 1080000, while the sum is 42.
The spelling of 52655504343 in words is "fifty-two billion, six hundred fifty-five million, five hundred four thousand, three hundred forty-three".
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