Base | Representation |
---|---|
bin | 110001001001100011… |
… | …000010111010000111 |
3 | 12001012212201011021021 |
4 | 301021203002322013 |
5 | 1331040011000041 |
6 | 40124355532011 |
7 | 3545530420516 |
oct | 611143027207 |
9 | 161185634237 |
10 | 52773531271 |
11 | 2042131215a |
12 | a2898ba007 |
13 | 4c905603a6 |
14 | 27a8c2467d |
15 | 158d101cd1 |
hex | c498c2e87 |
52773531271 has 2 divisors, whose sum is σ = 52773531272. Its totient is φ = 52773531270.
The previous prime is 52773531269. The next prime is 52773531299. The reversal of 52773531271 is 17213537725.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 52773531271 - 21 = 52773531269 is a prime.
It is a super-3 number, since 3×527735312713 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
Together with 52773531269, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (52773331271) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26386765635 + 26386765636.
It is an arithmetic number, because the mean of its divisors is an integer number (26386765636).
Almost surely, 252773531271 is an apocalyptic number.
52773531271 is a deficient number, since it is larger than the sum of its proper divisors (1).
52773531271 is an equidigital number, since it uses as much as digits as its factorization.
52773531271 is an evil number, because the sum of its binary digits is even.
The product of its digits is 308700, while the sum is 43.
The spelling of 52773531271 in words is "fifty-two billion, seven hundred seventy-three million, five hundred thirty-one thousand, two hundred seventy-one".
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