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5283113 = 113115493
BaseRepresentation
bin10100001001110100101001
3100221102001212
4110021310221
52323024423
6305122505
762622443
oct24116451
910842055
105283113
112a89310
121929435
13112c904
149b7493
156e5578
hex509d29

5283113 has 8 divisors (see below), whose sum is σ = 5949696. Its totient is φ = 4647600.

The previous prime is 5283101. The next prime is 5283139. The reversal of 5283113 is 3113825.

5283113 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 5283113 - 220 = 4234537 is a prime.

It is a super-2 number, since 2×52831132 = 55822565941538, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5283143) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7406 + ... + 8087.

It is an arithmetic number, because the mean of its divisors is an integer number (743712).

Almost surely, 25283113 is an apocalyptic number.

It is an amenable number.

5283113 is a deficient number, since it is larger than the sum of its proper divisors (666583).

5283113 is a wasteful number, since it uses less digits than its factorization.

5283113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15535.

The product of its digits is 720, while the sum is 23.

The square root of 5283113 is about 2298.5023384804. The cubic root of 5283113 is about 174.1659688268.

Adding to 5283113 its reverse (3113825), we get a palindrome (8396938).

The spelling of 5283113 in words is "five million, two hundred eighty-three thousand, one hundred thirteen".

Divisors: 1 11 31 341 15493 170423 480283 5283113