Base | Representation |
---|---|
bin | 110001010111000100… |
… | …000000010001011001 |
3 | 12001210200100221020101 |
4 | 301113010000101121 |
5 | 1332021032300113 |
6 | 40203055455401 |
7 | 3554252622166 |
oct | 612704002131 |
9 | 161720327211 |
10 | 53000275033 |
11 | 205283010a2 |
12 | a331827561 |
13 | 4cc851c4b4 |
14 | 27cada906d |
15 | 15a2e902dd |
hex | c57100459 |
53000275033 has 2 divisors, whose sum is σ = 53000275034. Its totient is φ = 53000275032.
The previous prime is 53000275001. The next prime is 53000275103. The reversal of 53000275033 is 33057200035.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 52894020169 + 106254864 = 229987^2 + 10308^2 .
It is a cyclic number.
It is not a de Polignac number, because 53000275033 - 25 = 53000275001 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 53000274992 and 53000275010.
It is not a weakly prime, because it can be changed into another prime (53000275333) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26500137516 + 26500137517.
It is an arithmetic number, because the mean of its divisors is an integer number (26500137517).
Almost surely, 253000275033 is an apocalyptic number.
It is an amenable number.
53000275033 is a deficient number, since it is larger than the sum of its proper divisors (1).
53000275033 is an equidigital number, since it uses as much as digits as its factorization.
53000275033 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9450, while the sum is 28.
Adding to 53000275033 its reverse (33057200035), we get a palindrome (86057475068).
The spelling of 53000275033 in words is "fifty-three billion, two hundred seventy-five thousand, thirty-three".
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