5300032300035 has 24 divisors (see below), whose sum is σ = 9321048544080. Its totient is φ = 2569712629440.

The previous prime is 5300032300021. The next prime is 5300032300061.

5300032300035 is nontrivially palindromic in base 10.

It is not a de Polignac number, because 5300032300035 - 2¹³ = 5300032291843 is a prime.

It is a super-2 number, since 2×5300032300035² (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5300032299978 and 5300032300014.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1460062180 + ... + 1460065809.

It is an arithmetic number, because the mean of its divisors is an integer number (388377022670).

Almost surely, 2^{5300032300035} is an apocalyptic number.

5300032300035 is a gapful number since it is divisible by the number (55) formed by its first and last digit.

5300032300035 is a deficient number, since it is larger than the sum of its proper divisors (4021016244045).

5300032300035 is a wasteful number, since it uses less digits than its factorization.

5300032300035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2920128019 (or 2920128008 counting only the distinct ones).

The product of its (nonzero) digits is 4050, while the sum is 24.

The spelling of 5300032300035 in words is "five trillion, three hundred billion, thirty-two million, three hundred thousand, thirty-five".