Base | Representation |
---|---|
bin | 11000000110100001001010… |
… | …11111101110001111011111 |
3 | 20221122210121202020222121202 |
4 | 30003100211133232033133 |
5 | 23421330034012134003 |
6 | 304420034424150115 |
7 | 14110106300411222 |
oct | 1403204537561737 |
9 | 227583552228552 |
10 | 53000525505503 |
11 | 1598443aa21934 |
12 | 5b3ba3490833b |
13 | 2375c0b098284 |
14 | d1334c2155b9 |
15 | 61d9ea5a9088 |
hex | 3034257ee3df |
53000525505503 has 2 divisors, whose sum is σ = 53000525505504. Its totient is φ = 53000525505502.
The previous prime is 53000525505439. The next prime is 53000525505541. The reversal of 53000525505503 is 30550552500035.
It is an a-pointer prime, because the next prime (53000525505541) can be obtained adding 53000525505503 to its sum of digits (38).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 53000525505503 - 26 = 53000525505439 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53000525505553) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26500262752751 + 26500262752752.
It is an arithmetic number, because the mean of its divisors is an integer number (26500262752752).
Almost surely, 253000525505503 is an apocalyptic number.
53000525505503 is a deficient number, since it is larger than the sum of its proper divisors (1).
53000525505503 is an equidigital number, since it uses as much as digits as its factorization.
53000525505503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 281250, while the sum is 38.
The spelling of 53000525505503 in words is "fifty-three trillion, five hundred twenty-five million, five hundred five thousand, five hundred three".
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