Base | Representation |
---|---|
bin | 111100010000010110101000… |
… | …1010010101000001100010111 |
3 | 2120111121202202002222200222201 |
4 | 1320200231101102220030113 |
5 | 1023432214030021103012 |
6 | 5115124413030505331 |
7 | 216432122336635336 |
oct | 17040552122501427 |
9 | 2514552662880881 |
10 | 530013213066007 |
11 | 1439733833a5990 |
12 | 4b540140805247 |
13 | 19998054385198 |
14 | 94c4ac2595d1d |
15 | 4141cd76b4857 |
hex | 1e20b514a8317 |
530013213066007 has 4 divisors (see below), whose sum is σ = 578196232435656. Its totient is φ = 481830193696360.
The previous prime is 530013213065957. The next prime is 530013213066019. The reversal of 530013213066007 is 700660312310035.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-530013213066007 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (530013213066047) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24091509684808 + ... + 24091509684829.
It is an arithmetic number, because the mean of its divisors is an integer number (144549058108914).
Almost surely, 2530013213066007 is an apocalyptic number.
530013213066007 is a deficient number, since it is larger than the sum of its proper divisors (48183019369649).
530013213066007 is a wasteful number, since it uses less digits than its factorization.
530013213066007 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 48183019369648.
The product of its (nonzero) digits is 68040, while the sum is 37.
The spelling of 530013213066007 in words is "five hundred thirty trillion, thirteen billion, two hundred thirteen million, sixty-six thousand, seven".
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