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53002555019311 is a prime number
BaseRepresentation
bin11000000110100100111100…
…11101101101000000101111
320221122222212012010222011211
430003102132131231000233
523421343213041104221
6304421012043455251
714110210503115132
oct1403223635550057
9227588765128154
1053002555019311
1115985291597677
125b40300527527
1323761726a7211
14d134a1994219
1561dab884b6e1
hex30349e76d02f

53002555019311 has 2 divisors, whose sum is σ = 53002555019312. Its totient is φ = 53002555019310.

The previous prime is 53002555019299. The next prime is 53002555019321. The reversal of 53002555019311 is 11391055520035.

53002555019311 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 53002555019311 - 215 = 53002554986543 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53002555019321) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26501277509655 + 26501277509656.

It is an arithmetic number, because the mean of its divisors is an integer number (26501277509656).

Almost surely, 253002555019311 is an apocalyptic number.

53002555019311 is a deficient number, since it is larger than the sum of its proper divisors (1).

53002555019311 is an equidigital number, since it uses as much as digits as its factorization.

53002555019311 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 101250, while the sum is 40.

The spelling of 53002555019311 in words is "fifty-three trillion, two billion, five hundred fifty-five million, nineteen thousand, three hundred eleven".