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530030255477 is a prime number
BaseRepresentation
bin1111011011010000100…
…00111101110101110101
31212200002201102202022212
413231220100331311311
532141000221133402
61043254215503205
753202433556522
oct7555020756565
91780081382285
10530030255477
1119486a296958
1286882087b05
133ac9b877208
141b9216a6149
15dbc2236952
hex7b6843dd75

530030255477 has 2 divisors, whose sum is σ = 530030255478. Its totient is φ = 530030255476.

The previous prime is 530030255449. The next prime is 530030255501. The reversal of 530030255477 is 774552030035.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 502831319236 + 27198936241 = 709106^2 + 164921^2 .

It is a cyclic number.

It is not a de Polignac number, because 530030255477 - 26 = 530030255413 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (530030251477) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265015127738 + 265015127739.

It is an arithmetic number, because the mean of its divisors is an integer number (265015127739).

Almost surely, 2530030255477 is an apocalyptic number.

It is an amenable number.

530030255477 is a deficient number, since it is larger than the sum of its proper divisors (1).

530030255477 is an equidigital number, since it uses as much as digits as its factorization.

530030255477 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 441000, while the sum is 41.

The spelling of 530030255477 in words is "five hundred thirty billion, thirty million, two hundred fifty-five thousand, four hundred seventy-seven".