Base | Representation |
---|---|
bin | 1111011011010000100… |
… | …01001010000000010111 |
3 | 1212200002201112021200021 |
4 | 13231220101022000113 |
5 | 32141000224232203 |
6 | 1043254220530011 |
7 | 53202434155012 |
oct | 7555021120027 |
9 | 1780081467607 |
10 | 530030305303 |
11 | 19486a320334 |
12 | 868820b0907 |
13 | 3ac9b893ab5 |
14 | 1b9216ba379 |
15 | dbc22465bd |
hex | 7b6844a017 |
530030305303 has 2 divisors, whose sum is σ = 530030305304. Its totient is φ = 530030305302.
The previous prime is 530030305289. The next prime is 530030305307. The reversal of 530030305303 is 303503030035.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-530030305303 is a prime.
It is a super-3 number, since 3×5300303053033 (a number of 36 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (530030305307) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265015152651 + 265015152652.
It is an arithmetic number, because the mean of its divisors is an integer number (265015152652).
Almost surely, 2530030305303 is an apocalyptic number.
530030305303 is a deficient number, since it is larger than the sum of its proper divisors (1).
530030305303 is an equidigital number, since it uses as much as digits as its factorization.
530030305303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6075, while the sum is 25.
Adding to 530030305303 its reverse (303503030035), we get a palindrome (833533335338).
The spelling of 530030305303 in words is "five hundred thirty billion, thirty million, three hundred five thousand, three hundred three".
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