53004113 has 4 divisors (see below), whose sum is σ = 56122020. Its totient is φ = 49886208.

The previous prime is 53004101. The next prime is 53004137. The reversal of 53004113 is 31140035.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 31140035 = 5 ⋅6228007.

It can be written as a sum of positive squares in 2 ways, for example, as 39225169 + 13778944 = 6263^2 + 3712^2 .

It is a cyclic number.

It is not a de Polignac number, because 53004113 - 2⁴ = 53004097 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (17), and also a Moran number because the ratio is a prime number: 3117889 = 53004113 / (5 + 3 + 0 + 0 + 4 + 1 + 1 + 3).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 53004091 and 53004100.

It is not an unprimeable number, because it can be changed into a prime (53004163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1558928 + ... + 1558961.

It is an arithmetic number, because the mean of its divisors is an integer number (14030505).

Almost surely, 2^53004113 is an apocalyptic number.

It is an amenable number.

53004113 is a deficient number, since it is larger than the sum of its proper divisors (3117907).

53004113 is a wasteful number, since it uses less digits than its factorization.

53004113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3117906.

The product of its (nonzero) digits is 180, while the sum is 17.

The square root of 53004113 is about 7280.3923658001. The cubic root of 53004113 is about 375.6382919024.

Adding to 53004113 its reverse (31140035), we get a palindrome (84144148).

The spelling of 53004113 in words is "fifty-three million, four thousand, one hundred thirteen".