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530044254520519 is a prime number
BaseRepresentation
bin111100010000100101000101…
…1100000011000010011000111
32120111201201212102221222101011
41320201022023200120103013
51023433221113124124034
65115150545144543051
7216434301513641614
oct17041121340302307
92514651772858334
10530044254520519
111439855624a7122
124b546164481a87
131999ac6044004b
1494c63c905d50b
154142a0295c864
hex1e2128b8184c7

530044254520519 has 2 divisors, whose sum is σ = 530044254520520. Its totient is φ = 530044254520518.

The previous prime is 530044254520513. The next prime is 530044254520523. The reversal of 530044254520519 is 915025452440035.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-530044254520519 is a prime.

It is a super-3 number, since 3×5300442545205193 (a number of 45 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (530044254520513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265022127260259 + 265022127260260.

It is an arithmetic number, because the mean of its divisors is an integer number (265022127260260).

Almost surely, 2530044254520519 is an apocalyptic number.

530044254520519 is a deficient number, since it is larger than the sum of its proper divisors (1).

530044254520519 is an equidigital number, since it uses as much as digits as its factorization.

530044254520519 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4320000, while the sum is 49.

The spelling of 530044254520519 in words is "five hundred thirty trillion, forty-four billion, two hundred fifty-four million, five hundred twenty thousand, five hundred nineteen".