Base | Representation |
---|---|
bin | 111100010000100101000101… |
… | …1100000011000010011001011 |
3 | 2120111201201212102221222101022 |
4 | 1320201022023200120103023 |
5 | 1023433221113124124043 |
6 | 5115150545144543055 |
7 | 216434301513641621 |
oct | 17041121340302313 |
9 | 2514651772858338 |
10 | 530044254520523 |
11 | 1439855624a7126 |
12 | 4b546164481a8b |
13 | 1999ac60440052 |
14 | 94c63c905d511 |
15 | 4142a0295c868 |
hex | 1e2128b8184cb |
530044254520523 has 2 divisors, whose sum is σ = 530044254520524. Its totient is φ = 530044254520522.
The previous prime is 530044254520519. The next prime is 530044254520567. The reversal of 530044254520523 is 325025452440035.
It is an a-pointer prime, because the next prime (530044254520567) can be obtained adding 530044254520523 to its sum of digits (44).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 530044254520523 - 22 = 530044254520519 is a prime.
It is not a weakly prime, because it can be changed into another prime (530044254520513) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265022127260261 + 265022127260262.
It is an arithmetic number, because the mean of its divisors is an integer number (265022127260262).
Almost surely, 2530044254520523 is an apocalyptic number.
530044254520523 is a deficient number, since it is larger than the sum of its proper divisors (1).
530044254520523 is an equidigital number, since it uses as much as digits as its factorization.
530044254520523 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2880000, while the sum is 44.
The spelling of 530044254520523 in words is "five hundred thirty trillion, forty-four billion, two hundred fifty-four million, five hundred twenty thousand, five hundred twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •