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530044350141 = 3377946753493
BaseRepresentation
bin1111011011010010001…
…10101110111010111101
31212200010200221211120110
413231221012232322331
532141012323201031
61043255441540233
753202664432035
oct7555106567275
91780120854513
10530044350141
11194877243439
1286886944679
133aca1770757
141b9234d48c5
15dbc35bcc46
hex7b691aeebd

530044350141 has 8 divisors (see below), whose sum is σ = 706912829280. Its totient is φ = 353269385552.

The previous prime is 530044350137. The next prime is 530044350169. The reversal of 530044350141 is 141053440035.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 530044350141 - 22 = 530044350137 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 530044350099 and 530044350108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (530044350541) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 23365410 + ... + 23388083.

It is an arithmetic number, because the mean of its divisors is an integer number (88364103660).

Almost surely, 2530044350141 is an apocalyptic number.

It is an amenable number.

530044350141 is a deficient number, since it is larger than the sum of its proper divisors (176868479139).

530044350141 is a wasteful number, since it uses less digits than its factorization.

530044350141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 46757275.

The product of its (nonzero) digits is 14400, while the sum is 30.

Adding to 530044350141 its reverse (141053440035), we get a palindrome (671097790176).

The spelling of 530044350141 in words is "five hundred thirty billion, forty-four million, three hundred fifty thousand, one hundred forty-one".

Divisors: 1 3 3779 11337 46753493 140260479 176681450047 530044350141