Base | Representation |
---|---|
bin | 111100010000101000101111… |
… | …1110010100110110000001011 |
3 | 2120111202111010222101021200220 |
4 | 1320201101133302212300023 |
5 | 1023433333210411113103 |
6 | 5115154324521201123 |
7 | 216435000303135045 |
oct | 17041213762466013 |
9 | 2514674128337626 |
10 | 530052111035403 |
11 | 143988924282030 |
12 | 4b5477976301a3 |
13 | 1999b913025718 |
14 | 94c6932656a95 |
15 | 4142d12563c53 |
hex | 1e2145fca6c0b |
530052111035403 has 128 divisors (see below), whose sum is σ = 869024203683840. Its totient is φ = 283421419438080.
The previous prime is 530052111035333. The next prime is 530052111035417. The reversal of 530052111035403 is 304530111250035.
It is not a de Polignac number, because 530052111035403 - 28 = 530052111035147 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (33).
It is not an unprimeable number, because it can be changed into a prime (530052111035423) by changing a digit.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 127723125 + ... + 131807817.
It is an arithmetic number, because the mean of its divisors is an integer number (6789251591280).
Almost surely, 2530052111035403 is an apocalyptic number.
530052111035403 is a deficient number, since it is larger than the sum of its proper divisors (338972092648437).
530052111035403 is a wasteful number, since it uses less digits than its factorization.
530052111035403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4084949.
The product of its (nonzero) digits is 27000, while the sum is 33.
Adding to 530052111035403 its reverse (304530111250035), we get a palindrome (834582222285438).
The spelling of 530052111035403 in words is "five hundred thirty trillion, fifty-two billion, one hundred eleven million, thirty-five thousand, four hundred three".
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