Base | Representation |
---|---|
bin | 1100101000110… |
… | …1111010110111 |
3 | 10200202012012011 |
4 | 3022031322313 |
5 | 102032310403 |
6 | 5132105051 |
7 | 1212402256 |
oct | 312157267 |
9 | 120665164 |
10 | 53010103 |
11 | 27a17303 |
12 | 15905187 |
13 | aca0533 |
14 | 707c79d |
15 | 49c1a6d |
hex | 328deb7 |
53010103 has 2 divisors, whose sum is σ = 53010104. Its totient is φ = 53010102.
The previous prime is 53010071. The next prime is 53010107. The reversal of 53010103 is 30101035.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 53010103 - 25 = 53010071 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53010107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26505051 + 26505052.
It is an arithmetic number, because the mean of its divisors is an integer number (26505052).
Almost surely, 253010103 is an apocalyptic number.
53010103 is a deficient number, since it is larger than the sum of its proper divisors (1).
53010103 is an equidigital number, since it uses as much as digits as its factorization.
53010103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 45, while the sum is 13.
The square root of 53010103 is about 7280.8037331053. The cubic root of 53010103 is about 375.6524416761.
Adding to 53010103 its reverse (30101035), we get a palindrome (83111138).
The spelling of 53010103 in words is "fifty-three million, ten thousand, one hundred three".
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