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53010213 = 317670071
BaseRepresentation
bin1100101000110…
…1111100100101
310200202012100020
43022031330211
5102032311323
65132105353
71212402504
oct312157445
9120665306
1053010213
1127a173a3
1215905259
13aca05b9
14707c83b
1549c1ae3
hex328df25

53010213 has 4 divisors (see below), whose sum is σ = 70680288. Its totient is φ = 35340140.

The previous prime is 53010203. The next prime is 53010227. The reversal of 53010213 is 31201035.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 53010213 - 29 = 53009701 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 53010192 and 53010201.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53010203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8835033 + ... + 8835038.

It is an arithmetic number, because the mean of its divisors is an integer number (17670072).

Almost surely, 253010213 is an apocalyptic number.

It is an amenable number.

53010213 is a deficient number, since it is larger than the sum of its proper divisors (17670075).

53010213 is a wasteful number, since it uses less digits than its factorization.

53010213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17670074.

The product of its (nonzero) digits is 90, while the sum is 15.

The square root of 53010213 is about 7280.8112872124. The cubic root of 53010213 is about 375.6527015117.

Adding to 53010213 its reverse (31201035), we get a palindrome (84211248).

The spelling of 53010213 in words is "fifty-three million, ten thousand, two hundred thirteen".

Divisors: 1 3 17670071 53010213