Base | Representation |
---|---|
bin | 111100010001000011110110… |
… | …0001000101101010010010111 |
3 | 2120111222001100021120212001102 |
4 | 1320202013230020231102113 |
5 | 1023440311343323330143 |
6 | 5115241150541220315 |
7 | 216442130264036225 |
oct | 17042075410552227 |
9 | 2514861307525042 |
10 | 530110300214423 |
11 | 143a00574584525 |
12 | 4b556b16b6169b |
13 | 199a42575743b6 |
14 | 94c9692817b15 |
15 | 41445bad220b8 |
hex | 1e221ec22d497 |
530110300214423 has 2 divisors, whose sum is σ = 530110300214424. Its totient is φ = 530110300214422.
The previous prime is 530110300214399. The next prime is 530110300214477. The reversal of 530110300214423 is 324412003011035.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 530110300214423 - 232 = 530106005247127 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (530110300214483) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265055150107211 + 265055150107212.
It is an arithmetic number, because the mean of its divisors is an integer number (265055150107212).
Almost surely, 2530110300214423 is an apocalyptic number.
530110300214423 is a deficient number, since it is larger than the sum of its proper divisors (1).
530110300214423 is an equidigital number, since it uses as much as digits as its factorization.
530110300214423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8640, while the sum is 29.
Adding to 530110300214423 its reverse (324412003011035), we get a palindrome (854522303225458).
The spelling of 530110300214423 in words is "five hundred thirty trillion, one hundred ten billion, three hundred million, two hundred fourteen thousand, four hundred twenty-three".
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