Base | Representation |
---|---|
bin | 110001010111101110… |
… | …001010001000001101 |
3 | 12001211110011100120012 |
4 | 301113232022020031 |
5 | 1332031344403303 |
6 | 40204132403005 |
7 | 3554445555152 |
oct | 612756121015 |
9 | 161743140505 |
10 | 53011325453 |
11 | 20533569479 |
12 | a335476465 |
13 | 4cca8bb1c8 |
14 | 27cc644229 |
15 | 15a3e245d8 |
hex | c57b8a20d |
53011325453 has 2 divisors, whose sum is σ = 53011325454. Its totient is φ = 53011325452.
The previous prime is 53011325443. The next prime is 53011325461. The reversal of 53011325453 is 35452311035.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 53004471529 + 6853924 = 230227^2 + 2618^2 .
It is a cyclic number.
It is not a de Polignac number, because 53011325453 - 214 = 53011309069 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53011325413) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26505662726 + 26505662727.
It is an arithmetic number, because the mean of its divisors is an integer number (26505662727).
Almost surely, 253011325453 is an apocalyptic number.
It is an amenable number.
53011325453 is a deficient number, since it is larger than the sum of its proper divisors (1).
53011325453 is an equidigital number, since it uses as much as digits as its factorization.
53011325453 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 27000, while the sum is 32.
Adding to 53011325453 its reverse (35452311035), we get a palindrome (88463636488).
The spelling of 53011325453 in words is "fifty-three billion, eleven million, three hundred twenty-five thousand, four hundred fifty-three".
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