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53011325453 is a prime number
BaseRepresentation
bin110001010111101110…
…001010001000001101
312001211110011100120012
4301113232022020031
51332031344403303
640204132403005
73554445555152
oct612756121015
9161743140505
1053011325453
1120533569479
12a335476465
134cca8bb1c8
1427cc644229
1515a3e245d8
hexc57b8a20d

53011325453 has 2 divisors, whose sum is σ = 53011325454. Its totient is φ = 53011325452.

The previous prime is 53011325443. The next prime is 53011325461. The reversal of 53011325453 is 35452311035.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 53004471529 + 6853924 = 230227^2 + 2618^2 .

It is a cyclic number.

It is not a de Polignac number, because 53011325453 - 214 = 53011309069 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53011325413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26505662726 + 26505662727.

It is an arithmetic number, because the mean of its divisors is an integer number (26505662727).

Almost surely, 253011325453 is an apocalyptic number.

It is an amenable number.

53011325453 is a deficient number, since it is larger than the sum of its proper divisors (1).

53011325453 is an equidigital number, since it uses as much as digits as its factorization.

53011325453 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27000, while the sum is 32.

Adding to 53011325453 its reverse (35452311035), we get a palindrome (88463636488).

The spelling of 53011325453 in words is "fifty-three billion, eleven million, three hundred twenty-five thousand, four hundred fifty-three".