Base | Representation |
---|---|
bin | 11000000110110101101001… |
… | …01010111011111011110010 |
3 | 20221200211222210200021001220 |
4 | 30003122310222323323302 |
5 | 23422020041441143100 |
6 | 304425053245205510 |
7 | 14110645552122432 |
oct | 1403326452737362 |
9 | 227624883607056 |
10 | 53011517521650 |
11 | 159890706a72a6 |
12 | 5b41ba1b60896 |
13 | 2376c7045893c |
14 | d13ab20082c2 |
15 | 61de405bcaa0 |
hex | 3036b4abbef2 |
53011517521650 has 48 divisors (see below), whose sum is σ = 131469461532000. Its totient is φ = 14136308104960.
The previous prime is 53011517521619. The next prime is 53011517521661. The reversal of 53011517521650 is 5612571511035.
It is a Curzon number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 22352026 + ... + 24609674.
It is an arithmetic number, because the mean of its divisors is an integer number (2738947115250).
Almost surely, 253011517521650 is an apocalyptic number.
53011517521650 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
53011517521650 is an abundant number, since it is smaller than the sum of its proper divisors (78457944010350).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53011517521650 is a wasteful number, since it uses less digits than its factorization.
53011517521650 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2414203 (or 2414198 counting only the distinct ones).
The product of its (nonzero) digits is 157500, while the sum is 42.
The spelling of 53011517521650 in words is "fifty-three trillion, eleven billion, five hundred seventeen million, five hundred twenty-one thousand, six hundred fifty".
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