Base | Representation |
---|---|
bin | 110001010111110001… |
… | …000000110100000111 |
3 | 12001211111120101000100 |
4 | 301113301000310013 |
5 | 1332032042324420 |
6 | 40204200415143 |
7 | 3554455122555 |
oct | 612761006407 |
9 | 161744511010 |
10 | 53012073735 |
11 | 20533a2a695 |
12 | a3357774b3 |
13 | 4ccaac098a |
14 | 27cc79abd5 |
15 | 15a4021190 |
hex | c57c40d07 |
53012073735 has 24 divisors (see below), whose sum is σ = 91981721520. Its totient is φ = 28244143872.
The previous prime is 53012073703. The next prime is 53012073739. The reversal of 53012073735 is 53737021035.
53012073735 is a `hidden beast` number, since 530 + 1 + 20 + 73 + 7 + 35 = 666.
It is not a de Polignac number, because 53012073735 - 25 = 53012073703 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 53012073735.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53012073739) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 558925 + ... + 646854.
It is an arithmetic number, because the mean of its divisors is an integer number (3832571730).
Almost surely, 253012073735 is an apocalyptic number.
53012073735 is a deficient number, since it is larger than the sum of its proper divisors (38969647785).
53012073735 is a wasteful number, since it uses less digits than its factorization.
53012073735 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1206767 (or 1206764 counting only the distinct ones).
The product of its (nonzero) digits is 66150, while the sum is 36.
The spelling of 53012073735 in words is "fifty-three billion, twelve million, seventy-three thousand, seven hundred thirty-five".
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