Base | Representation |
---|---|
bin | 1111011011011100000… |
… | …00100100100101101011 |
3 | 1212200100102202122000121 |
4 | 13231232000210211223 |
5 | 32141144403333120 |
6 | 1043311541144111 |
7 | 53205013633624 |
oct | 7555600444553 |
9 | 1780312678017 |
10 | 530126621035 |
11 | 194909725810 |
12 | 868aa3bb037 |
13 | 3acb581765b |
14 | 1b9303cca4b |
15 | dbca91e5aa |
hex | 7b6e02496b |
530126621035 has 8 divisors (see below), whose sum is σ = 693983940336. Its totient is φ = 385546633440.
The previous prime is 530126621027. The next prime is 530126621039.
530126621035 is nontrivially palindromic in base 10.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 530126621035 - 23 = 530126621027 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (530126621039) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4819332864 + ... + 4819332973.
It is an arithmetic number, because the mean of its divisors is an integer number (86747992542).
Almost surely, 2530126621035 is an apocalyptic number.
530126621035 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
530126621035 is a deficient number, since it is larger than the sum of its proper divisors (163857319301).
530126621035 is a wasteful number, since it uses less digits than its factorization.
530126621035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9638665853.
The product of its (nonzero) digits is 32400, while the sum is 34.
The spelling of 530126621035 in words is "five hundred thirty billion, one hundred twenty-six million, six hundred twenty-one thousand, thirty-five".
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