Base | Representation |
---|---|
bin | 110001010111111000… |
… | …110100110000111101 |
3 | 12001211122102102001201 |
4 | 301113320310300331 |
5 | 1332033103342113 |
6 | 40204312335501 |
7 | 3554511412042 |
oct | 612770646075 |
9 | 161748372051 |
10 | 53014121533 |
11 | 205350a918a |
12 | a3363a4591 |
13 | 4ccb359aa9 |
14 | 27ccb711c9 |
15 | 15a42c7cdd |
hex | c57e34c3d |
53014121533 has 2 divisors, whose sum is σ = 53014121534. Its totient is φ = 53014121532.
The previous prime is 53014121513. The next prime is 53014121591. The reversal of 53014121533 is 33512141035.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 34529815684 + 18484305849 = 185822^2 + 135957^2 .
It is a cyclic number.
It is not a de Polignac number, because 53014121533 - 29 = 53014121021 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53014121513) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26507060766 + 26507060767.
It is an arithmetic number, because the mean of its divisors is an integer number (26507060767).
Almost surely, 253014121533 is an apocalyptic number.
It is an amenable number.
53014121533 is a deficient number, since it is larger than the sum of its proper divisors (1).
53014121533 is an equidigital number, since it uses as much as digits as its factorization.
53014121533 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5400, while the sum is 28.
Adding to 53014121533 its reverse (33512141035), we get a palindrome (86526262568).
The spelling of 53014121533 in words is "fifty-three billion, fourteen million, one hundred twenty-one thousand, five hundred thirty-three".
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