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53014424133 = 3117272209763
BaseRepresentation
bin110001010111111001…
…111110101001000101
312001211122222210011010
4301113321332221011
51332033143033013
640204323032433
73554514112206
oct612771765105
9161748883133
1053014424133
1120535295570
12a33650b719
134ccb434748
1427ccc0d5ad
1515a43377c3
hexc57e7ea45

53014424133 has 16 divisors (see below), whose sum is σ = 77217993216. Its totient is φ = 32085744240.

The previous prime is 53014424117. The next prime is 53014424159. The reversal of 53014424133 is 33142441035.

It is not a de Polignac number, because 53014424133 - 24 = 53014424117 is a prime.

It is a super-2 number, since 2×530144241332 (a number of 22 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 53014424133.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53014424833) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1080891 + ... + 1128872.

It is an arithmetic number, because the mean of its divisors is an integer number (4826124576).

Almost surely, 253014424133 is an apocalyptic number.

It is an amenable number.

53014424133 is a deficient number, since it is larger than the sum of its proper divisors (24203569083).

53014424133 is a wasteful number, since it uses less digits than its factorization.

53014424133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2210504.

The product of its (nonzero) digits is 17280, while the sum is 30.

Adding to 53014424133 its reverse (33142441035), we get a palindrome (86156865168).

The spelling of 53014424133 in words is "fifty-three billion, fourteen million, four hundred twenty-four thousand, one hundred thirty-three".

Divisors: 1 3 11 33 727 2181 7997 23991 2209763 6629289 24307393 72922179 1606497701 4819493103 17671474711 53014424133