Base | Representation |
---|---|
bin | 110001010111111100… |
… | …010000111001101101 |
3 | 12001211201010012221021 |
4 | 301113330100321231 |
5 | 1332033321220323 |
6 | 40204343534141 |
7 | 3554522155615 |
oct | 612774207155 |
9 | 161751105837 |
10 | 53015023213 |
11 | 20535664679 |
12 | a33675a351 |
13 | 4ccb5b4329 |
14 | 27ccd27a45 |
15 | 15a440505d |
hex | c57f10e6d |
53015023213 has 2 divisors, whose sum is σ = 53015023214. Its totient is φ = 53015023212.
The previous prime is 53015023211. The next prime is 53015023247. The reversal of 53015023213 is 31232051035.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 31033402569 + 21981620644 = 176163^2 + 148262^2 .
It is a cyclic number.
It is not a de Polignac number, because 53015023213 - 21 = 53015023211 is a prime.
Together with 53015023211, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53015023211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26507511606 + 26507511607.
It is an arithmetic number, because the mean of its divisors is an integer number (26507511607).
Almost surely, 253015023213 is an apocalyptic number.
It is an amenable number.
53015023213 is a deficient number, since it is larger than the sum of its proper divisors (1).
53015023213 is an equidigital number, since it uses as much as digits as its factorization.
53015023213 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2700, while the sum is 25.
Adding to 53015023213 its reverse (31232051035), we get a palindrome (84247074248).
The spelling of 53015023213 in words is "fifty-three billion, fifteen million, twenty-three thousand, two hundred thirteen".
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