Base | Representation |
---|---|
bin | 11111100110100… |
… | …011100010011111 |
3 | 1100221122222200021 |
4 | 133212203202133 |
5 | 2041212410420 |
6 | 124340013011 |
7 | 16065426511 |
oct | 3746434237 |
9 | 1327588607 |
10 | 530200735 |
11 | 252314729 |
12 | 129691167 |
13 | 85aca55c |
14 | 505b7bb1 |
15 | 318317aa |
hex | 1f9a389f |
530200735 has 4 divisors (see below), whose sum is σ = 636240888. Its totient is φ = 424160584.
The previous prime is 530200717. The next prime is 530200751. The reversal of 530200735 is 537002035.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 530200735 - 25 = 530200703 is a prime.
It is a super-2 number, since 2×5302007352 = 562225638789080450, which contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53020069 + ... + 53020078.
It is an arithmetic number, because the mean of its divisors is an integer number (159060222).
Almost surely, 2530200735 is an apocalyptic number.
530200735 is a deficient number, since it is larger than the sum of its proper divisors (106040153).
530200735 is a wasteful number, since it uses less digits than its factorization.
530200735 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 106040152.
The product of its (nonzero) digits is 3150, while the sum is 25.
The square root of 530200735 is about 23026.0881393258. The cubic root of 530200735 is about 809.3693892765.
The spelling of 530200735 in words is "five hundred thirty million, two hundred thousand, seven hundred thirty-five".
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