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53020412143 = 197926791517
BaseRepresentation
bin110001011000010000…
…110100100011101111
312001212002021000011021
4301120100310203233
51332041211142033
640205055235011
73554616032026
oct613020644357
9161762230137
1053020412143
1120538705436
12a338518a67
134ccc75014a
1427cd92b8bd
1515a4b1bb2d
hexc584348ef

53020412143 has 4 divisors (see below), whose sum is σ = 53047205640. Its totient is φ = 52993618648.

The previous prime is 53020412129. The next prime is 53020412191. The reversal of 53020412143 is 34121402035.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 53020412143 - 213 = 53020403951 is a prime.

It is a super-2 number, since 2×530204121432 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53020412113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13393780 + ... + 13397737.

It is an arithmetic number, because the mean of its divisors is an integer number (13261801410).

Almost surely, 253020412143 is an apocalyptic number.

53020412143 is a deficient number, since it is larger than the sum of its proper divisors (26793497).

53020412143 is a wasteful number, since it uses less digits than its factorization.

53020412143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26793496.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 53020412143 its reverse (34121402035), we get a palindrome (87141814178).

The spelling of 53020412143 in words is "fifty-three billion, twenty million, four hundred twelve thousand, one hundred forty-three".

Divisors: 1 1979 26791517 53020412143